SoLuTiOn For CrYpTs by (M.R Kartheek & Bhanu Chander)
Click the problem to find the solution ……
March 2nd, 2013 at 03:51
cryptarithmetic multiplication puzzles
A BEGINNER IN CRYPTARITHMETICS
August 30th, 2013 at 11:45
please tell the tricks for begginners for such kind of problemS AS I AM FINDING A BIT DIFFICULT TO UNDERSTAND
March 2nd, 2013 at 03:53
cryptarithmetic multiplication questions u can find in this site 🙂 any dought just give a comment
July 31st, 2013 at 14:42
could you assist me i was unable to get into that crypt-arithmetic multiplication puzzles if u help me ill b thankful to u thnq in advance
August 1st, 2013 at 13:17
We r little busy in office works … but u will get help through mails ..
April 24th, 2014 at 21:38
hello Sampath, i confused so much for this problems, can u pls help me… thanks in advance
February 7th, 2014 at 19:22
I dont know dis type of question pls help with example
April 24th, 2014 at 21:40
hello Bhanu, i confused so much for this problems, can u pls help me… thanks in advance
March 19th, 2013 at 10:23
osm work .
March 19th, 2013 at 17:57
March 20th, 2013 at 08:16
could you please tell me the book from which you have chosen these problems and i have one more problem of type BIT*EGO= _ _ _ _ _( i don`t remember the next part ) if u have the question please share.
March 25th, 2013 at 08:58
April 20th, 2013 at 06:17
June 22nd, 2013 at 06:01
Do tell the solution of BIT * EGO
June 22nd, 2013 at 07:22
Will keep soon .. Mr shefali
July 17th, 2013 at 06:41
for some problems solution is not there like 16 15..i have solved it but have some little problem
July 17th, 2013 at 07:05
WHat problem do you have? just keep a comment
July 21st, 2013 at 11:53
dog * go=486 * 68
these are correct or not?plz tell me if anyone knows.. 🙂
September 9th, 2013 at 12:01
mention the whole crypto questn..
July 26th, 2013 at 11:58
July 27th, 2013 at 12:41
November 28th, 2013 at 18:39
this soln is wrong buddy.
November 28th, 2013 at 19:09
RED * AS = 247 * 15
i think this should be the answer.
September 13th, 2013 at 18:14
September 23rd, 2013 at 12:52
great job dude…. 🙂
September 26th, 2013 at 12:00
Can u please tell me how to solve these type of questions. My mail id is firstname.lastname@example.org
October 9th, 2013 at 14:02
can anyone tell the easy way to crack them..
October 9th, 2013 at 16:15
simply saying awesome puzzles n solutions!!!!
October 15th, 2013 at 03:38
i am a beginner and unable to understand could u pls assist me
October 17th, 2013 at 22:32
I am a beginner could u plz snd me any tricks or links to”email@example.com”
October 24th, 2013 at 04:15
Solution of 2nd last problem–
9 9 7
* 3 5
4 9 8 5
2 9 9 1 *
3 4 8 9 5
October 25th, 2013 at 15:46
plz help me i’m totally new to this topic ,so i want some basic notes about cryptarithematic notes…..thnx in advance
October 28th, 2013 at 15:00
plz help me i’m also new to this topic ,so i want some basic notes about cryptarithematic notes…..thnx in advance
November 27th, 2013 at 01:14
I N N 4 6 6
A T 3 8
A O R T 3 7 2 8
B A L T 1 3 9 8
B O O S T 1 7 7 0 8
(I N N)*T=AORT……. (4 6 6)*8=3 7 2 8
(I N N)*A=BALT………(4 6 6)*3=1 3 9 8
November 28th, 2013 at 18:40
someone plz explain me the RED * AS problem plzzz.
November 28th, 2013 at 19:11
aahh .. got it. it was easy. 😀
December 2nd, 2013 at 23:43
can any1 tell me solution of …….
December 3rd, 2013 at 11:19
can any one tell me the tricks,i am a beginner.
how to justify the value of letter.
December 3rd, 2013 at 12:00
Up to my knowledge this is the best procedure . Do practice in this way you will be perfect
December 3rd, 2013 at 11:32
plz reply me ……….fast????
December 3rd, 2013 at 16:31
A P R
* O C T
P U R A
R O J R
R E C U
R A A J A A
can anyone solve this plzz..
December 6th, 2013 at 18:42
A=4, P=3, R=2, O=5, C=6, T=7, U=0, J=9 its is an easy question try to solve to the fact that U is 0 or 5 and R<=4 and C=6 because even multiplication gives same result as multiflied
December 6th, 2013 at 18:48
can u plz explain how u have solved it..
December 6th, 2013 at 18:51
from where the problem begins. what is the first alphabet assigned number.
December 6th, 2013 at 19:06
got it 🙂 🙂
December 11th, 2013 at 12:45
D S P
L I E
S P S S
P E T A
P O D E
P N E D A S
is there anybody who can solve this and please if can do it then also share how 2 solve..!!
December 16th, 2013 at 21:25
really .. its awesome … i’m searching this for one week at last i got this link from facebook . u did great work . now i completely learned about crypt arithmetic. thank you so much …
December 19th, 2013 at 11:53
Thanks for the comment 🙂
December 16th, 2013 at 22:17
can u explain this ……
December 31st, 2013 at 19:41
Answr of AGE * OAT = 317*538
January 7th, 2014 at 19:39
how much time should one take to solve these question(s) in elitmus in order to have good time management…???
for me it takes 15mins or so
do you think it’s very slow?? or should i just leave this type of questions???
January 18th, 2014 at 09:54
Can u please tell me how to solve these type of questions. My mail id is firstname.lastname@example.org
January 25th, 2014 at 23:58
Hi please share how to solve these.
January 25th, 2014 at 23:59
Hi please share how to solve these problem
January 31st, 2014 at 13:09
hi please can you help to solve the problen if you have solutions please mailto email@example.com
Sayonayon Kumar Saha
January 31st, 2014 at 20:09
what would be the solution for DIG x IN = IGOPN ?
February 4th, 2014 at 14:50
Is there any specific book for cryptarithmatic questions?? Kindly suggest me, bcz i find it difficult 2 study and undrstand online.
Pravata Ranjan Dash
February 10th, 2014 at 19:43
in the multiplication problem 2…how will u know that U=6 and Y=4…….please tell me…..as written….[[second multiple (W H Y ) * U = (O Y P Y)
So, The number for U = 6 and Y is (2 , 4) Lets take the value of Y is 4 and replace it in figure.]]
February 17th, 2014 at 15:43
If WORLD + TRADE = CENTER then C+E+N+T+E+R = ?
February 24th, 2014 at 23:05
I am beginer . please let me know crypto arithmatic tricks,,,
April 5th, 2014 at 15:19
pls tell the trick behind this….
July 8th, 2014 at 15:30
how to solve these problems?can u help?
July 15th, 2014 at 18:13
A G E
* O A T
S O A R
H O G
G O T O
G E C O I R
July 16th, 2014 at 07:57
Thankuuuuuuu So much 🙂 U made it simple 🙂 ur blog rocks (Y)
July 16th, 2014 at 16:54
thanku 🙂 for the comment
July 20th, 2014 at 10:28
MAD * BE=AMID plz send me ans
July 20th, 2014 at 10:30
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